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Fix mkpath() ignoring mode when umask is more restrictive
mkpath(dir, 0755) with umask 0027 silently creates a 0750 directory, since mkdir(2) applies the umask to the requested mode. Callers pass an explicit mode and expect exactly that. Apply the mode with chmod() after each successful mkdir(). Signed-off-by: Joachim Wiberg <troglobit@gmail.com>
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@@ -50,6 +50,34 @@ int test_fmkpath(const char *subdir)
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return ret;
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}
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/* mkpath() must apply mode as given, not mode & ~umask */
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int test_umask(void)
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{
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const char *dirs[] = { BASEDIR "/um", BASEDIR "/um/sub", NULL };
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mode_t old = umask(0077);
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struct stat sb;
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int i, ret;
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ret = mkpath(dirs[1], 0755);
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umask(old);
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if (ret) {
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perror("Failed");
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return ret;
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}
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for (i = 0; dirs[i]; i++) {
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if (checkpath(dirs[i]) || stat(dirs[i], &sb))
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return 1;
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if ((sb.st_mode & 07777) != 0755) {
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fprintf(stderr, "Failed: %s mode %04o, expected 0755\n",
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dirs[i], sb.st_mode & 07777);
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return 1;
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}
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}
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return 0;
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}
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int main(void)
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{
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int i, ret = 0;
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@@ -66,14 +94,18 @@ int main(void)
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mkdir(BASEDIR, 0755);
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printf("Pass 1/2: makepath() =========================\n");
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printf("Pass 1/3: makepath() =========================\n");
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for (i = 0; list[i] && !ret; i++)
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ret |= test_makepath(list[i]);
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printf("Pass 2/2: fmkpath() ==========================\n");
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printf("Pass 2/3: fmkpath() ==========================\n");
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for (i = 0; list[i] && !ret; i++)
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ret |= test_fmkpath(list[i] + strlen(BASEDIR) + 1);
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printf("Pass 3/3: mkpath() with umask ================\n");
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if (!ret)
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ret |= test_umask();
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printf("Done: Cleaning up ============================\n");
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system("rm -rf " BASEDIR);
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